Discuss Calculation of thermal output??? in the Plumbing Jobs | The Job-board area at PlumbersForums.net
Joules confuse me, but 66.66 X 14 X 4 X 60 equals 224,000 BTU/hr Approx 67 Kw. This seems high. I would seek confirmation of flow rate or temp. diff.
Your DT is way to high which suggests a flow rate issue. The reason I asked about which heat pump you have is to understand its capabilities and whether or not it was an inverter driven compressor etc, not because I wanted to slag it of or suggest a different model.
When did you take the DT and under what conditions? You need to allow the heat pump to run for long enough for it to adjust to whatever load you're placing it under.
Good question. No idea. Would have thought it was a bit odd to display theoretical flow rate on a changing display that can be adjusted by user? Dunno.Unfamiliar with pump, but does the 4000 litre/hr. refer to theoretical flow against zero head resistance.
If, as you say in a later post, the flow is 4mÂł/hr that is 66.66 litres/min. However, my formula needs the flow in litres/sec so the output is 66.66/60 x 14 x 4.18 = 65kW or 65 J/sec. The output over one minute is therefore 3900 Joules. (I know it's the same as you got but, as one of my maths teachers used to say, "right answer, wrong method!")OK, I'm struggling a bit with the maths.... My figures are as follows:
Flow rate: 66.66 litres per minute
4000 seemed too round a figure for actual flow rate. Since posting I have goggled pump data and flow drops off considerably with head.
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